LATEX 数学公式总结_latex数学公式大全
LATEX 数学公式总结由刀豆文库小编整理,希望给你工作、学习、生活带来方便,猜你可能喜欢“latex数学公式大全”。
SUNLEY FORWARD
数学公式小结
请运行以下程序:
documentcla[11pt]{article} usepackage{CJK} usepackage{indentfirst} usepackage{latexsym} usepackage{bm} usepackage{amsmath,amymb,amsfonts} usepackage{wasysym} usepackage{xcolor} usepackage{cases}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %
重定义字体、字号命令
% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% newcommand{song}{CJKfamily{song}}
% 宋体
(Windows自带simsun.ttf)newcommand{fs}{CJKfamily{fs}}
% 仿宋体(Windows自带simfs.ttf)newcommand{kai}{CJKfamily{kai}}
% 楷体
(Windows自带simkai.ttf)newcommand{hei}{CJKfamily{hei}}
% 黑体
(Windows自带simhei.ttf)newcommand{li}{CJKfamily{li}}
% 隶书
(Windows自带simli.ttf)newcommand{you}{CJKfamily{you}}
% 幼圆
(Windows自带simyou.ttf)newcommand{chuhao}{fontsize{42pt}{baselineskip}selectfont}
% 字号设置 newcommand{xiaochuhao}{fontsize{36pt}{baselineskip}selectfont} % 字号设置 newcommand{yichu}{fontsize{32pt}{baselineskip}selectfont}
% 字号设置 newcommand{yihao}{fontsize{28pt}{baselineskip}selectfont}
% 字号设置 newcommand{erhao}{fontsize{21pt}{baselineskip}selectfont}
% 字号设置 newcommand{xiaoerhao}{fontsize{18pt}{baselineskip}selectfont} % 字号设置 newcommand{sanhao}{fontsize{15.75pt}{baselineskip}selectfont} % 字号设置 newcommand{xiaosanhao}{fontsize{15pt}{baselineskip}selectfont} % 字号设置 newcommand{sihao}{fontsize{14pt}{baselineskip}selectfont}
% 字号设置 newcommand{xiaosihao}{fontsize{12pt}{baselineskip}selectfont} % 字号设置 newcommand{wuhao}{fontsize{10.5pt}{baselineskip}selectfont}
% 字号设置 newcommand{xiaowuhao}{fontsize{9pt}{baselineskip}selectfont}
% 字号设置 newcommand{liuhao}{fontsize{7.875pt}{baselineskip}selectfont} % 字号设置 newcommand{qihao}{fontsize{5.25pt}{baselineskip}selectfont}
% 字号设置 %%%%%%%%%
END %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
SUNLEY FORWARD renewcommand{baselinestretch}{1.3}
begin{document} begin{CJK*}{GBK}{song} CJKtildeCJKindent
{heisanhao 数学公式举例:} bigskip
section{概述}
数学模式中的普通文本必须放入一个~LR 盒子里.如:
$ x^2+sin(x)=0 is a nonlinear equation$.$ x^2+sin(x)=0 mbox{ is a nonlinear equation} $.$ x^2+sin(x)=0 mbox{ 是一个非线性方程}$.section{行内公式} 勾股定理~begin{math}a^2+b^2=c^2end{math}~也称商高定理.勾股定理~(a^2+b^2=c^2)~也称商高定理.勾股定理~$a^2+b^2=c^2$~也称商高定理.section{行间公式} subsection{单行公式} begin{displaymath}
a^2+b^2=c^2.end{displaymath} [
a^2+b^2 = c^2.]
begin{equation}
a^2+b^2=c^2.end{equation} $$ a^2+b^2=c^2.eqno(*)$$ SUNLEY FORWARD $$ a^2+b^2=c^2.eqno(4a)$$
begin{equation}label{eq:square}
x^2+y^2=R^2.end{equation} 公式~ref{eq:square}~表示的是一个圆的标准方程.setcounter{equation}{5} begin{equation}label{lap}
-triangle u(x,y)= f(x,y),quad(x,y)inOmega.end{equation} 方程~eqref{lap}~则是一个椭圆型的偏微分方程.subsection{多行公式} begin{eqnarray*} x^2 + y^2 = R^2 2x + 3y = b end{eqnarray*}
begin{eqnarray} x^2 + y^2 & = & R^2 2x + 3y
& = & b end{eqnarray}
setlength{arraycolsep}{2.5pt} setcounter{equation}{1} begin{eqnarray} d(uv)& = &(uv)' dx
& = &(u'v+uv')dx
& = & v(u'dx)+u(v'dx)nonumber
setcounter{equation}{5}
& = & v du+u dv label{leibniz} end{eqnarray} 这样就得到了公式~(ref{leibniz}).section{角标: 上标与下标}
注意: 这里的角标命令必须在数学模式下使用!$$ SUNLEY FORWARD x_1, quad x_{11}, quad x_{11}^{22}, quad x_{m}^{(k)},quad {}^* x ^*, quad x^{m^n}, quad {x^x}^{x^x} $$
中文角标:qquad $ x^{mbox{scriptsize 平方}},quad x^{y^{mbox{tiny 平方}}} $
导数符号:qquad $ f^{prime} quadmbox{或者}quad f' $
section{分式}
出现在行内的分式: $(x+y)/2 $ 和~$ frac{x+y}{2} $, 第二个分式用的是一级角标字体.分式中的分式: $frac{frac{x}{x+y}}{x+y+z}$, 字体会更小, 但最小为二级角标字体.行间公式
$$ frac{x+y}{2},qquad frac{frac{x}{x+y}}{x+y+z} $$
section{根式}
$ sqrt{x},quad sqrt{1+sqrt{2}} $
$ surd{x},quad surd{1+sqrt{2}} $
当被开方式字符高度不同时, 根号线会在不同水平线上, 如: $sqrt{a}, sqrt{b}$.解决办法: 加入{hei数学支柱}~ textbackslash{}mathstrutfootnote{宽度为~0,高度与圆括号相同}, 例: $sqrt{a}, sqrt{b},quad sqrt{amathstrut}, sqrt{bmathstrut}$.section{求和与积分}
newcommand{dx}{mathrm{d},x} $$ SUNLEY FORWARD int_a^b f(x)mathrm{d}x,quad oint_a^b f(x)mathrm{d}x,quad $$ $$ intlimits_a^b f(x)mathrm{d}x,quad ointlimits_a^b f(x)mathrm{d}x,quad $$
直立的积分号: $$ varint_a^b f(x)dx, quad iint_a^b f(x)dx, quad iiint_a^b f(x)dx,quad varoint_a^b f(x)dx,quad oiint_a^b f(x)dx,quad $$ $$ varintnolimits_a^b f(x)dx, quad iintnolimits_a^b f(x)dx, quad iiintnolimits_a^b f(x)dx,quad varointnolimits_a^b f(x)dx,quad oiintnolimits_a^b f(x)dx,quad $$
section{数学重音符号}
newcommand{ml}[1]{texttt{textcolor{blue}{char` #1}}}
renewcommand{arraystretch}{1.2} setlength{tabcolsep}{6pt} begin{tabular}{|p{0.4textwidth}|p{0.4textwidth}|}hline
ml{hat}{a}~$to hat{a}$ & ml{bar}{a}~$to bar{a}$
ml{dot}{a}~$to dot{a}$ & ml{ddot}{a}~$to ddot{a}$
ml{tilde}{a}~$to tilde{a}$ & ml{vec}{a}~$to vec{a}$
ml{breve}{a}~$to breve{a}$ & ml{check}{a}~$to check{a}$
ml{acute}{a}~$to acute{a}$ & ml{grave}{a}~$to grave{a}$
ml{mathring}{a}~$to mathring{a}$ &
hline end{tabular} bigskip
加宽的帽子和波浪号: $widehat{hello},quad widetilde{good}$ SUNLEY FORWARD
section{上划线、下划线及类似符号}
$$ overline{overline{a}^2 + underline{ab} + bar{b}^2} $$ bigskip
$$ underbrace{a+overbrace{b+dots+b}^{mmbox{scriptsize个}}+ c}_
{20mbox{scriptsize个}} $$
section{堆积符号} $$ vec{x} stackrel{mathrm{def}}{=}(x_1,ldots,x_n)$$
section{可以变大的定界符} 略
section{阵列}
一个简单的阵列(行内): $ begin{array}{ccc} 11 & 12 & 13 21 & 22 & 23 end{array} $
阵列(行间)$$ left(begin{array}{ccc} 11 & 12 21 & 22 & 23 end{array} right)$$
一个较复杂的例子 $$ SUNLEY FORWARD left{ begin{array}{ccccccccc} a_{11}x_1 &+& a_{12}x_2 &+& cdots &+& a_{1n}x_n &=& b_1 a_{21}x_1 &+& a_{22}x 2 &+& cdots &+& a_{2n}x_n &=& b_2 multicolumn{9}{c}{dotfill} a_{n1}x_1 &+& a_{n2}x_2 &+& cdots &+& a_{nn}x_n &=& b_n end{array} right.$$
另一个较复杂的例子 begin{equation} f(x)=left{ begin{array}{ll}
x & mbox{当~$xge 0$~时;}
-x & mbox{其它情形} end{array} right.end{equation}
section{添加宏包 quad $backslash mbox{usepackage{cases}}$} subsection{cases 环境}
begin{numcases}{|x|=} x, & for $xgeq0$-x, & for $x
begin{subnumcases}{|x|=} x, & for $xgeq0$-x, & for $x
begin{subnumcases}{ } x, & for $xgeq0$-x, & for $x
begin{equation} f(x)=begin{cases} 1 &-1
SUNLEY FORWARD subsection{subequations~环境} begin{subequations}
begin{align}
(a+b)^2 & =a^2+b^2
a+b+c)^2 & =a^2+b^2+c^2+2ab+2ac+2bc
end{align}
begin{equation}
(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
end{equation} end{subequations}
begin{equation}(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3 end{equation}
end{CJK*} end{document}